given a right-angled triangle with area 30 square centimeters and one of the legs of the right-angled triangle has 5cm, of the sum of the altitudes of the triangle can be expressed as a/b where gcd(a, b)=1. find a+b. geometry

See explanation

Step-by-step explanation:

If A = 30 = 1/2ab = 1/2(5)(b)

60 = 5b

b = 12

a/b = 5/12

a + b = 5 + 12 = 17

b if for most of the graph

d if y intercept

step-by-step explanation:

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)