An executive drove from his home at an average speed of 35 mph to an airport where a helicopter was waiting. The executive then boarded the helicopter and flew to the corporate offices at an average speed of 78 mph. The entire distance from his home to the office was 169.5 if the executive spent the same amount of time in the car as he did the helicopter how long did it take the executive to get to work

3 hours

Step-by-step explanation:

Speed is the ratio of distance traveled to time taken, it is given as:

Speed = distance / time

An executive drove from his home at an average speed of 35 mph to an airport where a helicopter was waiting. He then took the helicopter and flew to the corporate offices at an average speed of 78 mph. Given that the executive spent the same amount of time in the car as he did the helicopter how long did it take the executive to get to work.

Let the amount of time the executive spent in the car be t hours, therefore the amount of time spent in the helicopter = t hours.

For car:

Speed = distance / time

35 = distance () / t

For helicopter:

Speed = distance / time

78 = distance () / t

The total distance traveled = 169.5 miles

The time taken for the executive to get to work = time spent on car + time spent on helicopter = 1.5 + 1.5 = 3 hours

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

(2,20) means that the 2 is 2 hours and 20 is 20$. so there both 20$ for 2 hours only the same price. like it says. so, the dunk tank and the bounce house are the same price (20$) for the same amount of time (2 hours).

hope i