Please answer this question now

Measure of arc CD = 112°

Step-by-step explanation:

Since quadrilateral ABCD is a cyclic quadrilateral,

m∠A + m∠C = 180°

129° + m∠C = 180°

m∠C = 180° - 129°

m∠C = 51°

Since, m(arc BD) = 2(m∠C) [Since measure of the arc is double of its inscribed angle]

                           = 2(51°)

                           = 102°

Since, m(arc BD) + m(arc CD) + m(arc BC) = 360°

102° + m(arc CD) + 146° = 360°

m(arc CD) = 360° - (102° + 146°)

                = 112°

Therefore, measure of arc CD is 112°.

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

(3x-8) or (3x+8)

step-by-step explanation: