If area of a rhombus is 336 cm and one of its diagonal is 14 cm, find its perimeter.

The perimeter of the rhombus is the sum of its side lengths

The perimeter of the Rhombus is 100 cm

The length of one of its diagonal is given as:

And the area is given as:

Assume the other diagonal is q.

The area of the rhombus is represented as:

So, we have:

This gives

Divide both sides by 7

Rewrite as:

The perimeter (P) of the rhombus is calculated as:

So, we have:

Evaluate the squares

Take positive root of 2500

Hence, the perimeter of the Rhombus is 100 cm

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The perimeter of the Rhombus is 100 cm

Step-by-step explanation:

First of all, we will need to find the length of the other diagonal.

let’s call the diagonals p and q

Mathematically, the area of the Rhombus is;

pq/2 = Area of Rhombus.

Let’s call the missing diagonal p

So;

(p * 14)/2 = 336

14p = 672

p = 672/14

p = 48 cm

Now, we can find the perimeter of the Rhombus using these diagonals.

Mathematically;

P = 2 √(p^2 + q^2)

Substituting these values, we have;

P = 2 √(14)^2 + (48^2)

P = 2 √(2500)

P = 2 * 50

P = 100 cm

b. f(x) = –√x + 3this is the correct answer