A square has a perimeter of 8 and one vertex at (2, 2). What could be the location of another vertex of this shape? A) (1, 5) B) (-2, 2) C) (2, 3) D) (0, 0)

D) (0,0)

Step-by-step explanation:

It is a square so each side is 2 units because

8/4 = 2

If the first point is at (2,2) we need to find which other point is 2 away from the first one. Or two away from where that point would be since there are 3 other corners.

We can rule out A and C because they are an odd number away. B is too far away because he's distance is 4.

So the other point is (0,0)

a) t'(-3, 6) and v'(0, 3)  

step-by-step explanation:

false

step-by-step explanation:

the reason i say this is because for a certain length of sides you can pick any two and the length is wither equal or greater than the third side and in this case it's not.

3 + 5 = 8

8 is smaller than 9 which is the third side.

hope this : )