The speed(S) of a car varies partly directly as its mass(M) and partly directly as the quantity (Q) of fuel in it. When the speed is 80km/hr, the mass is 220kg and the quantity of fuel is 30litres, when the speed is 60km/hr, the mass is 300kg and the quantity of fuel is 40 litres. Find the volume of fuel if the speed is 100km/hr and the mass 250kg. DO NOT WRITE TRASH I WILL REPORT YOU

Quantity of fuel is 24 L, based on the model S=2400/Q when S=100

Step-by-step explanation:

If the output power of the car remains constant, the speed would reduce as the masses increase, which is the shown in the observed data.

Hence S does NOT vary directly with the mass and quantity, but varies INVERSELY with the mass and fuel (which has a mass).

Many models are possible to fit the results.  Product models with a single constant k

S(m,q) = kmq  and S(m,q) = k/mq  

do not fit both observation, hence rejected.

A possible  model with two constants is shown below

S(m,q) = k1/m + k2/q(1)

1.  m=220, q=30 =>  80 = k1/220 + k2/30 (2)

2. m=300, q=40 =>  60 = k1/300 + k2/40 (3)

Solve system (2) and (3) gives k1=0, k2 = 2400.

So it appears that the speed is independent of the mass (m) [unlikely], but inversely proportional to the quantity (q) of fuel, giving

S(q) = 2400/q

When speed = 100 km/h, and mass = 250 kg,  substitute

100 = 2400/q => q=2400/100 = 24

step-by-step explanation:

for volume, add base x height x width

it's 100

step-by-step explanation:

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

  n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the  14th  row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100

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