The aquarium has 6 fewer yellow fish than green fish. 40 percent of the fish are yellow. How many green fish are in the aquarium? Show your work.

The total number of green fish in the aquarium is 18 fishes

let

number of green fish = g

number of yellow fish = y

y = g - 6. (1)

y = 40% of (y + g)

y = 0.40(y + g) (2)

equate both equations

g - 6 = 0.40(y + g)

g - 6 = 0.40y + 0.40g

g - 6 = 0.40(g - 6) + 0.40g

g - 6 = 0.40g - 2.4 + 0.40g

g - 0.40g - 0.40g = -2.4 + 6

0.2g = 3.6

g = 3.6/0.2

g = 18

Therefore,

number of green fish = g

= 18

number of yellow fish = y

= g - 6

= 18 - 6

= 12 fishes

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step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.