A particular geometric sequence has strictly decreasing terms. After the first term, each successive term is calculated by multiplying the previous term by $\frac{m}{7}$. If the first term of the sequence is positive, how many possible integer values are there for $m$?

6 possible integers

Step-by-step explanation:

Given

A decreasing geometric sequence

Required

Determine the possible integer values of m

Assume the first term of the sequence to be positive integer x;

The next sequence will be

The next will be;

The nth term will be

For each of the successive terms to be less than the previous term;

then must be a proper fraction;

This implies that:

Where 7 is the denominator

The sets of is and their are 6 items in this set

Hence, there are 6 possible integer

after 1 year: 221 deer

step-by-step explanation:

30% of 170 is 51. 170+51=221