Suppose that 10 fair coins are tossed. Find the numbers of ways of obtaining exactly 1 heads. Round the answer to the nearest whole number

10

Step-by-step explanation:

Given : Total number of coins tossed = 10

Possible outcomes to toss a coin = Head or tail

Number of possible outcomes =

Number of ways of obtaining exactly 1 heads =     [using combinations ]

=10

Hence, the numbers of ways of obtaining exactly 1 heads= 10

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1