Write the other side of this equation so it's true for no values of x;

1/2(6x-10)-x =

1/2(6x-10)-x = 2x +3

Step-by-step explanation:

1/2(6x-10)-x =

Distribute

3x -5 -x

2x -5

We need to other side to be of the form 2x - constant where the constant is not equal to 5

2x-5 = 2x+3

Subtract 2x from each side

-5 =3

This is not  true so there is no solution

john has 55 candy left.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?