12. Find the values in the interval [-n/2, n] that satisfy the equation.
arctan (V3/3) = x
с
a. since tan (n/6) = 13/3, X = n/6
b. since sin (-1/4)= -V2/2, x = -1/4
c. since cos (3n/2) = -1/2, X = 3n/2
d. since cos 0 = 1, x = 0
e. since cos (1/4) = V2/2, X = n/4
13

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