What is an equation of the line that is parallel to y=3x-8 and passes through the point (4, -5)

Hi there! :)

y = 3x - 17.

Step-by-step explanation:

To write an equation parallel to y = 3x - 8, we need the slope as well as the coordinates of a point to solve for the "b" value in y = mx + b:

A line parallel to y = 3x - 8 contains the same slope, or m = 3.

Plug in the coordinates in (4, -5) into "x" and "y" in the equation y = mx + b respectively:

-5 = 3(4) + b

-5 = 12 + b

Simplify:

-5 - 12 = b

b = -17.

Rewrite the equation:

y = 3x - 17.

2nd one in the first row is correct

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°