If 1 gallon of water is added to 6 quarts of a mixture of alcohol and water that is 50% alcohol, what percent alcohol is the resulting mixture? Will mark brainlist

The percentage of alcohol in the resulting mixture is 30%

Step-by-step explanation:

The equation given are;

Volume of added water = 1 gallon = 3.79 litres = 4 quarts

Volume of mixture of alcohol = 6 quarts = 5.68 litres

Concentration of the alcohol in 6 quarts = 50%

Given that the mixture of alcohol and water is 50% alcohol and 50% water, we  have;

Volume of 100% alcohol in 5.68 liters = 0.5× 5.68 = 2.84 litres = 3 quartz

Total volume of the final solution = 5.68 + 3.78 = 9.46 litres = 10 quarts

Percentage by volume of 100% alcohol in total volume of the resultant solution = 3 quarts/((4 + 6) quarts) × 100 = 3/10 × 100 = 30%

The percentage of alcohol in the resulting mixture = 30%.

arrange the equations with like terms in columns.

analyze the coefficients of x or y.

add the equations and solve for the remaining variable.

substitute the value into either equation and solve.

check the solution.

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