Graph the parabola. y=x^2 -4 where do i put the points

To generate a point, you plug in a number for x to get the corresponding y value.

If x = 0 for instance, then the y value is...

y = x^2 - 4

y = 0^2 - 4 ... x is replaced with 0

y = 0 - 4

y = -4

So x = 0 and y = -4 pair up to get the point (0,-4). This is the y intercept as the parabola crosses the y axis here. It turns out that this is also the vertex point as it is the lowest point on the parabola.

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If x = 1, then,

y = x^2 - 4

y = 1^2 - 4

y = 1 - 4

y = -3

meaning (x,y) = (1,-3) is another point on this line.

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Repeat for x = 2

y = x^2 - 4

y = 2^2 - 4

y = 4-4

y = 0

Since we got a y output of 0, we have found an x intercept located at (2,0). The other x intercept is (-2,0).

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The idea is to generate as many points as possible. Plot all of the points on the same xy coordinate grid. Then draw a curve through those points the best you can. You should get what you see in the diagram below. I used GeoGebra to make the graph. Desmos is another handy tool I recommend.

Note: the more points you generate, the more accurate the graph will be

answer is 67%

step-by-step explanation:

idk lol

step-by-step explanation: