An Article a Florida newspaper reported on the topics that teenagers most want to discuss with their parents. The findings, the results of a poll, showed that 46% would like more discussion about the family’s financial situation, 37% would like to talk about school, and 30%would like to talk about religion. These and other sampling were based on 522 teenagers. Estimate the proportion of all teenagers who want more family discussions about school. Use a 90% confidence level. Express the answer in the form P hat+- E

The estimate is  

Step-by-step explanation:

From the question we are told that  

    The sample size is  n =  522

    The sample proportion of students  would like to talk about school is  

  Given that the confidence level is  90 % then the level of significance can be mathematically evaluated as

Next we obtain the critical value of   from the normal distribution table, the value is  

Generally the margin of error can be mathematically represented as

=>            

=>            

Generally the estimate the proportion of all teenagers who want more family discussions about school at 90% confidence level is  

substituting values

answer:

step-by-step explanation:

step-by-step explanation:

x-intercept:

(

−

1

+

√

7

,

0

)

,

(

−

1

−

√

7

,

0

)

y-intercept:

(

0

,

−

6

)