Our school's girls volleyball team has 14 players, including a set of 3 triplets: Alicia, Amanda, and Anna. In how many ways can we choose 6 starters if exactly two of the triplets are in the starting lineup?

990 ways to choose 6 starters out of 14 with exactly two of the three triplets.

Step-by-step explanation:

Ways to choose 2 of the triplets

= C(3,2) = 3! / (2!1!) = 3

Ways to choose the remaining 4 starters out of 11 players left

= C(11,4) = 11! / (4!7!) = 330

Total number of ways to choose 6 starters

= 3*330 = 990

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %

2 1/2 feet

step-by-step explanation: