A father's age is 4 times as that of his son's age. in 5 years time, the father will be 3 times as old as his son. what are their present ages?

Step-by-step explanation:

Let, present age of son be 'x'

present age of father be 'y'

y = 4x→ equation ( i )

After five years,

Son's age = x + 5

father's age = y + 5

According to Question,

Put the value of y from equation ( i )

Distribute 3 through the parentheses

Move variable to L.H.S and change it's sign

Similarly, Move constant to R.H.S. and change its sign

Collect like terms

Calculate the difference

Now, put the value of X in equation ( i ) in order to find the present age of father

plug the value of X

Calculate the product

Therefore,

Present age of son = 10

present age of father = 40

Hope this helps..

Best regards!!

y=mx+b

step-by-step explanation:

m slope

b y-intercept