2. IQS = 4 and QR is a perpendicular bisector of TS , determined which of the following claims is true

RS=5 TRUE

RS=4 FALSE (it’s 5)

ST=10 FALSE (it’s 8)

QR=4 FALSE (its 3)

Step-by-step explanation:

First, we have to determine the sides of the triangle.

4x-3=2x+1

4x-2x=1+3

2x=4

x=2

SO, RS=4x-3=4(2)-3=8-3=5

RT=2(x)+1=2(2)+1=5

QR=4²+b²=5².    16+b²=25.    b²=25-16.    b²=9.     b=3

CLAIMS:

RS=5 TRUE

RS=4 FALSE (it’s 5)

ST=10 FALSE (it’s 8)

QR=4 FALSE (its 3)

(-1,-0.5)

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.