A coin is tossed and -sided die numbered 1 through is rolled. Find the probability of tossing a and then rolling a number greater than . The probability of tossing a and then rolling a number greater than is nothing.

hello your question has some missing parts here is the complete question

A coin is tossed and an eight-sided die numbered 1 through 8 is rolled. Find the probability of tossing tail and then rolling a number greater than 6. The probability of tossing a tail and then rolling a number greater than 6 is? Round to three decimal places as needed

Answer : 0.5,   0.25,  0.125

Step-by-step explanation:

A coin when tossed has only two outcomes which are ( Head or tail )

a)Therefore the probability of tossing a tail = 1/2 = 0.5

A die having eight sides when tossed will have 8 outcomes

B) Therefore the probability of rolling a number greater than 6

p( x > 6) = p(7) + p(8) = 1/8 + 1/8 = 0.25

C) The probability of tossing a tail and then rolling a number greater than 6 is

= p( x > 6 ) * p( tail )

= 0.25 * 0.5 = 0.125

the statemwnt is the company makes small and large snow cone cups.

large=it holds more then the small

small=it holds less then the large

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )