Algebra 1 help please Solve 19a + 11b = 12a + 15 for a.
Select one:
a. 77 – 11b)
b. (15 + 11b 1/7
c. 7 ( 15 – 11b )
d. (15 – 11b)

a = (15-11b)/7

Step-by-step explanation:

19a + 11b = 12a + 15

Subtract 12a from each side

19a-12a + 11b = 12a-12a + 15

7a +11b = 15

Subtract 11b from each side

7a+11b-11b = 15 -11b

7a = 15-11b

Divide by 7

7a/7 = (15-11b)/7

a = (15-11b)/7

215.92 dollars is the answer

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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