Find x, y, and z please!!

A.

x= sqrt(40)  ( =6.325 to 3 dec. places)

y = sqrt(56)  (= 7.483 to 3 dec. places)

z = sqrt(140)  (= 11.832 to 3 dec. places)

B.

x = sqrt(24)   (= 4.899 to 3 dec. places)

y = sqrt(28)    (=5.292 to 3 dec. places)

z = sqrt(168)    (= 12.961 to 3 dec. places)

Step-by-step explanation:

Assuming x is an altitude of the triangles.

Using metric relations,

A.

x^2=4*10=40 => x= sqrt(40) = 2sqrt(10) (= 6.325 to 3 dec. places)

y^2=4*(10+4) => y = sqrt(56) (= 7.483 to 3 dec. places)

z^2=10*(10+4) => z = sqrt(140) (= 11.832 to 3 dec. places)

check: y^2 + z^2 = (10+4)^2  ok.

similarly

B.

x^2= 2*12=24  => x = sqrt(24) = 2 sqrt(6)    (= 4.899 to 3 dec. places)

y^2 = 2*(12+2) = 28  => y = sqrt(28) = 2 sqrt(7)  (= 5.292 to 3 dec. places)

z^2 = 12*(12+2) = 168  =>   z = sqrt(168) = 4sqrt(42)   (= 12.961 to 3 dec. places)

check: y^2 + z^2 = 28+168 = 196  = (2+12)^2   ok.

answer: was that a question or answer?

step-by-step explanation:

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right