In the circle below, QS is a diameter. Suppose m QR = 68° and m<QRT= 56°. Find the following.

Step-by-step explanation:

A) ∠QRS = 90 degrees (The angle of the triangle opposite to the diameter is always 90)

Given that QR = 68 degrees

So,

∠RSQ =

∠RSQ = 68/2

∠RSQ = 34 degrees

Now, Finding ∠RQS

∠RQS = 180-90-34

∠RQS = 56 degrees

B) ∠SRT = ∠QRS - ∠QRT

=> ∠QRS = 90 (Mentioned above) , ∠QRT = 56 (Given)

So,

∠SRT = 90-56

∠SRT = 34 degrees

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14