An exterior angle of a triangle is 120° and one of the interior opposite angle is 50°. Find the other two angles of the triangle.

interior angle (2)= 70

interior angle (3)= 60

Step-by-step explanation:

Given:

exterior angle=120°

interior angle (1)=50°

Required:

interior angle (2)=?

interior angle (3)=?

Formula:

exterior angle=interior angle (1) + interior angle (2)

Solution:

exterior angle=interior angle (1)+ interior angle (2)

120°=50°+interior angle (2)

120°+50°=interior angle (2)

70°=interior angle (2)

interior angle (3)= 180°-interior angle (1)- interior angle (2)

interior angle (3)=180°-50°+70°

interior angle (3)=180°-120°

interior angle (3)= 60°

Theorem:

Theorem 1.16

The measure of an exterior angle of a triangle is greater than either of the measures of the remote interior angles.

Hope this helps ;) ❤❤❤

Step-by-step explanation:

In ∆ ABC,

∠ACD = ∠ABC + ∠BAC

120° = 50° + ∠BAC

∠BAC = 120° - 50°

∴∠BAC = 70°

∴ 3rd ∠ACB = 180° - (50° + 70°)

= 180° - 120°

= 50°

Hence, the other two angles of the triangle are 70° and 50°.

Hope this helps!!

45

step-by-step explanation:

smple