Best answer will be rated brainliest

A.  6 and 30

B.  8 and 28

Step-by-step explanation:

we know that the area of the three squares must satisfy the Pythagorean Theorem so c² = a² + b²

where

c²  is the area of the largest square

a² and b² are the areas of the smaller squares

now.. 36² = a² + b2

The sum of the areas of the smaller squares must be equal to 36

therefore

6 and 30 >>>> could be the areas of the smaller squares (6 + 30 = 36)

8 and 28 >>>> could be the areas of the smaller squares (8 + 28 = 36)

hope it clears your mind.

Please mark as the brainliest

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8