How many triangles does a=6 b=10 A=33° create?

2 triangles are possible.

Step-by-step explanation:

Given

a=6

b=10

A=33°

To find:

Number of triangles possible ?

Solution:

First of all, let us use the sine rule:

As per Sine Rule:

And let us find the angle B.

This value is in the 1st quadrant i.e. acute angle.

One more value for B is possible in the 2nd quadrant i.e. obtuse angle which is: 180 - 65.44 =

For the value of , let us find :

Let us find side c using sine rule again:

So, one possible triangle is:

a = 6, b = 10, c = 10.89

A=33°, A=65.44°, C=81.56°

For the value of , let us find :

Let us find side c using sine rule again:

So, second possible triangle is:

a = 6, b = 10, c = 5.91

A=33°, A=114.56°, C=32.44°

So, answer is : 2 triangles are possible.

for b its (t) and c its (d)

step-by-step explanation: