The average student loan debt is reported to be $25,235. A student belives that the student loan debt is higher in her area. She takes a random sample of 100 college students in her area and determines the mean to be $27,524 and the standard devition to be $6000. Is there sufficient evidence to support the student' claim at a 5% significance level?

We reject the students claim because the P-value is less than the significance level.

Step-by-step explanation:

First of all let's define the hypothesis;

Null hypothesis;H0; μ = 25,235

Alternative hypothesis;Ha; μ > 25,235

Now, let's find the test statistic. Formula is;

t = (x' - μ)/(σ/√n)

We are given;

x' = 27,524

μ = 25,235

σ = 6000

n = 100

Thus;

t = (27524 - 25235)/(6000/√100)

t = 2289/600

t = 3.815

So from online p-value calculator as attached, using t=3.815, DF = 100-1 = 99 and significance level of 0.05, the P-value is gotten as p = 0.000237.

The p-value is less than the significance level of 0.05. Thus,we reject the students claim.

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square