Given: AB ∥ DC , m CB =62°, m∠DAB=104° Find: m∠DEA, m∠ADB

m∠DEA = 62° and m∠ADB = 318°

Step-by-step explanation:

, - (Given)

m∠CB = 62° (Given)

we have;

m∠CB ≅ m∠DA (parallel lines congruent arc theorem)

m∠DA = 62° = m∠DEA

m∠DAB = 104° Given

Therefore, m∠AB = 104° - 62° = 42° (sum of angle)

m∠DC = 360 - 62 - 62 - 42 = 194°  (sum of angles around a circle)

m∠ADB = 360° - m∠AB (sum of angles around a circle)

Therefore, m∠ADB = 360° - 42° = 318°

The required angles are;

m∠DEA = 62° and m∠ADB = 318°

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.