Mathematics, 29.07.2020 20:01, mostman077

3x2 +4=0 whats the answer?

Answers: 3

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answered: angelreji4702

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Hi my lil bunny!

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Lets do this step by step.

Simplify $\frac{3x - 2}{x} -4$ .

To write -4 as a fraction with a common denominator, multiply by $\frac{x}{x}$

$\frac{3x - 2}{x} - 4 . \frac{x}{x} 0$

Combine -4 and $\frac{x}{x}$ .

$\frac{3x - 2}{x} + \frac{-4x}{x} 0$

Combine the numerators over the common denominator.

$\frac{3x - 2 -4x}{x} 0$

Subtract 4x from 3x.

$\frac{-x -2}{x} 0$

Factor -1 out of -x.

$\frac{-(-x) -2}{x} 0$

Rewirte -2 as -1 (2).

$\frac{-(x -1 (2)}{x} 0$

Factor -1 out of - (x) - 1 (2).

$\frac{-(x + 2)}{x} 0$

Simplify the Expression.

_______________

Rewrite - ( x + 2 ) as -1 ( x + 2 ) .

$\frac{-1 ( x+ 2)}{x} 0$

Move the negative in front of the fraction.

$- \frac{x + 2}{x} 0$

Then your going to find all the values where the expression switches from negative to positive by setting each factor equal to 0 and solving.

$x = 0\\x + 2 = 0$

Subtract 2 from both sides of the equation.

x = -2

Solve for each factor to find the values where the absolute value expression goes from negative to positive.

$x = 0 \\x = -2$

Consolidate the solutions.

x = 0, -2

________________

Find the domain of $\frac{3x - 2}{x} -4$

_________________

Set the denominator in $\frac{3x - 2}{x}$ equal to 0 to find where the expression is undefined.

x = 0

The domain is all values of x that make the expression defined.

( - ∞, 0 ) ∪ ( 0 , ∞)

Use each root to create test intervals.

$x < -2 \\-2 < x < 0 \\x 0$

|Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.|

Test a value on the interval -2 < x < 0 to see if it makes the inequality true.

Ans : True

Test a value on the interval x > 0 to see if it makes the inequality true.

Ans : False

Test a value on the interval x < -2 to see if it makes the inequality true.

Ans : False

Compare the intervals to determine which ones satisfy the original inequality.

$x < -2 = False\\-2 < x < 0 = True\\x 0 = False$

The solution consists of all of the true intervals.

-2 < x < 0

The result can be shown in multiple forms.

Inequality Form: -2 < x< 0

Interval Notation: ( -2 , 0 )

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Hope this helped you.

Could you maybe give brainliest..?

❀*May*❀

answered: Guest

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

$ab^2+ac^2=bc^2$

$ab^2+ac^2=x^2$ )

triangle abd and cba are similar,

$\frac{ab}{bc}=\frac{bd}{ab}$

$ab^2=bc\cdot bd$

$25=bc\cdot bd$ (2)

triangle cad and cba are similar,

$\frac{ac}{bc}=\frac{cd}{ac}$

$ac^2=bc\cdot dc$

$7\times 7=bc\cdot dc$

$49=bc\cdot dc$ )

using (1), (2) and (3), we get

$25+49=x^2$

$74=x^2$

hence proved.

therefore option 2 is correct.

answered: Guest

step-by-step explanation:

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