Last year Peter spent a total of 8 1/6 hours on community service. Visits to old folks' homes made up 4/7 of the total time. How much time did he spend in visiting old folks homes? B) This year Peter plans to spend 1 1/5 of his time spent last year on community service.
(i) Find the time he will spend on community service.
(ii) How much more time will he spend this year than last year?

A. 4 2/3 hours

B. (i) 9 4/5 hours

(ii) 1 19/30

Step-by-step explanation:

Firstly, to find the number of hours he used in visiting old folks, what we have to do is to multiply the fraction of hours he used by the total number of hours.

Mathematically, that would be;

4/7 * 8 1/6

8 1/6 is same as 49/6

So the number of hours he spent visiting old folks would be ;

49/6 * 4/7 = 14/3 = 4 2/3 hours

B. What we do here is simply multiply the fraction now by what he spent last year.

That would be 1 1/5 * 8 1/6 hours

= 6/5 * 49/6 = 49/5 = 9 4/5 hours

ii) Now we want to know how much more time will be spent this year than last year.

What to do here simply is to subtract the time taken last year from what we have this year

That would be;

49/5 - 49/6 = 49/30 = 1 19/30

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64