g Suppose that twenty different hypothesis tests for whether jellybeans cause acne are conducted. In order that the probability of one or more type I error between these should be at most 0.05, at most what significance level should be used for each of them?

The level of significance to be used is α = 0.0025

Step-by-step explanation:

Here, we are interested in calculating the the level of significance which at most must be used for each of the hypothesis test

We proceed as follows;

P(type 1 error) = α

From the question, n = number of hypotheses = 20

P( of one or more type one error) ≤ 0.05

1- P(no type one error) ≤ 0.05

Hence;

1- (1-α)^20 ≤ 0.05

(1-α)^20 ≥ 0.95

1- α ≥ 0.997438621223

α ≤ 0.00256

Thus α = 0.0025

saving = more money

step-by-step explanation:

if you have 100 bucks, and you want to buy a candy bar, even if you have one at home, if you choose not to buy it, you save.

~courtney

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1