A city has a population of 220,000 people. Suppose that each year the population grows by 7.25%. What will the population be after 13 years?

546496.76

Step-by-step explanation:

Given the following :

Current population = 220,000

Population growth rate per year = 7.25%

Population size after 13 years =?

Using the compounding formula :

A = P(1 + r)^t

Where ;

A = final population size

P = current population size

r = growth rate

t = time or period

A = P(1 + r)^t

A = 220,000 ( 1 + 7.25/100)^13

A = 220,000 ( 1 + 0.0725)^13

A = 220,000 (1.0725)^13

A = 220,000(2.484076)

A = 546496.760

The population will be about 546,497 people

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)