Assume that a procedure yields a binomial distribution with a trial repeated n=18 times. Use either the binomial probability formula (or a technology like Excel or StatDisk) to find the probability of k=5 successes given the probability p=0.51 of success on a single trial. (Report answer accurate to 4 decimal places.)

0.0278 is the probability

Step-by-step explanation:

Okay, here we want to find the probability of 5 successes

The best way to go about this is by using the Bernoulli trial

So is p = probability of success = 0.51

Then q = probability of failure = 1-0.51 = 0.49

Mathematically, the Bernoulli approximation for k = 5 out of n = 18 is set up as follows;

P(k = 5) = nCk • p^k • q^(n-k)

P(k = 5) = 18C5 * 0.51^5 * 0.49^13

P(k = 5) = 0.027751047366 which is 0.0278 to 4 decimal places

70,000 + 6,000 + 800 + 30

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.