(((Please help, asap. Giving brainliest.))) Explain how you can classify shapes, using the distance and slope formula. <—I got this part I just really need an example. Provide examples to support your response 

Step-by-step explanation:

Try to use the distance formula to determine whether the sides are congruent. So take every pair of consecutive vertices and apply the distance formula. So you will have which, in any, sides are congruent.

Use the slope formula to determine which sides are parallel or perpendicular or neither of those. If the slopes are equal the sides are parallel, if the product of the slopes is - 1 the sides are perpendicular. In any other case the sides are neither parallel nor perpendicular.

With that and the definitions of the shapes you will be able to classify shapes.

To write a full example would be very long .

An easy one might be this as an example:

Given the  points (0,0), (2,0), (2,2) and (0,2), classify the shape.

When you apply the distance formula: you will find 2 for all the sides, so they are all congruent.

When you apply the slope formula you will find two pair of parallel sides, and the sides that intersects are perpendicular.

Therefore... the classification of the shape is a square.

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !

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step-by-step explanation: