g The equation for the change of position of a train starting at x = 0 m is given by The dimensions of b are Select one: a. L-1T-1 b. LT-1 c. T-3 d. LT-2 e. LT-3

The dimensions of b from the given equation are; B: LT⁻¹

The complete question is;

The equation for the change of position of a train starting at x = 0 m is given by x =(1/2)at² + bt³. The dimensions of b are__

Now, in that equation above, b represents the velocity of the motion. Now, the formula for velocity is;

Velocity = Distance/Time

Now, distance is also called Length and represented by L in basic parameters units while Time is represented by T.

Thus, the dimensions of b are; L/T or expressed as LT⁻¹

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Step-by-step explanation:

The question is incomplete. Here is the complete question,

The equation for the change of position of a train starting at x = 0 m is given by x =(1/2)at² + bt³. The dimensions of b are__

from the equation of motion given, the constant b is the velocity of the body. For us to get the dimension of b, we have to find the dimension of the velocity .

Since velocity is the rate of change of displacement of a body, then;

VELOCITY = DISPLACEMENT/TIME

displacement is measured in metres while time in seconds.

expressing the formula in terms of its fundamental unit,

v = metre/secs

Since the fundamental quantity of the metre is length (L) and that of seconds is the time (T); the dimensions is expressed as;

V = L/T

V = L * 1/T

V = L * T⁻¹

V = LT⁻¹

Hence the dimension of b is  LT⁻¹.

Note that the dimension of a body is written in terms of its fundamental quantities.

no he doesnt because "-16' is negatiive

step-by-step explanation: