Rectangle JKLM is rotated 90° clockwise about the origin. On a coordinate plane, rectangle J K L M has points (negative 4, 1), (negative 1, 1), (negative 1, negative 1), (negative 4, negative 1). What are the coordinates of J’? J’(–1, –4) J’(4, –1) J’(1, 4) J’(4, 1)

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

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y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x

the answer is: -22 also a

hope i

-lavira: )