A prism has a volume of 238 cubic millimeters. Which is the correct substitution for finding the length of the prism?

D. V = l w h. 238 = l times 8 and one-half times 3 and one-half

Step-by-step explanation:

A prism has a volume of 238 cubic millimeters.

A prism has a length of l millimeters, height of 3 and one-half millimeters, and width of 8 and one-half millimeters.

Which is the correct substitution for finding the length of the prism?

A. V = l w h. 238 = l + 8 and one-half + 3 and one-half

B. V = l w h. V = 238 times 8 and one-half times 3 and one-half

C. V = l w h. l times 8 and one-half times 3 and one-half

D. V = l w h. 238 = l times 8 and one-half times 3 and one-half

From the question

V=lwh

Volume of a prism=length)(width)(height)

Volume=238

l= l mm

w= 8 1/2

h= 3 1/2

Substituting all the values

V=lwh

238= l * 8 1/2 * 3 1/2

D. V = l w h. 238 = l times 8 and one-half times 3 and one-half

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.