Which of the following are solutions to the quadratic equation? Check all that apply. x2 + x-12 = 0

A. -1
B. 28
C. 2
D. 4
E. 3
F. -4

x= -4   x= 3

Step-by-step explanation:

x2 + x-12 = 0

Factor

What 2 numbers multiply to -12 and add to 1

4 * -3 = -12

4+3 = 1

( x+4) ( x-3) =0

Using the zero product property

x= -4   x= 3

E, F

Step-by-step explanation:

x² + x - 12 = 0

Let’s factor left side.

Find 2 numbers that multiply to get -12 and add to get 1

4 ×  -3 = -12

4 + 3 = 1

x² - 3x + 4x - 12 = 0

x(x - 3) + 4(x - 3) = 0

(x + 4)(x - 3) = 0

Set factors equal to 0.

x + 4 = 0

x = -4

x - 3 = 0

x = 3

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

answer: y=0 if that is what u r looking for