Find a general solution of the system Bold x prime left parenthesis t right parenthesisx?(t)equals=Bold Upper A Bold x left parenthesis t right parenthesisAx(t)
for the given matrix
Bold Upper AA.
Bold Upper AAequals=Start 2 By 2 Table 1st Row 1st Column 15 2nd Column 6 2nd Row 1st Column negative 39 2nd Column negative 15 EndTable
15 6
?39 ?15
Bold x left parenthesis t right parenthesisx(t)equals=nothing
?(Use parentheses to clearly denote the argument of each? function.)

Evaluate 8x2 + 9x − 1 2x3 + 3x2 − 2x dx. solution since the degree of the numerator is less than the degree of the denominator, we don't need to divide. we factor the denominator as 2x3 + 3x2 − 2x = x(2x2 + 3x − 2) = x(2x − 1)(x + 2). since the denominator has three distinct linear factors, the partial fraction decomposition of the integrand has the form† 8x2 + 9x − 1 x(2x − 1)(x + 2) = correct: your answer is correct. to determine the values of a, b, and c, we multiply both sides of this equation by the product of the denominators, x(2x − 1)(x + 2), obtaining 8x2 + 9x − 1 = a correct: your answer is correct. (x + 2) + bx(x + 2) + cx(2x − 1).