if the edges of the base of a rectangular prism are 8 cm and 6 cm, and the diagonal is 10√2, what is the volume of the solid?

221.12 cm^3

Step-by-step explanation:

Imagine that you have the 6cm side of the prism base facing you, and that you cut the prism in half through the vertex.  Doing this will form two triangles.  The hypotenuse of the triangle is the same as the "diagonal" that is 10√2 cm.  The base of this triangle is half of the 6" side, or 3 cm.

Use the Pythagorean Theorem to determine the height (h) of the prism:

h^2 + 3^2 = (10√2)^2, or

h^2 = 200-9 = 191

Then the height is √191 cm

and the base area is 6cm times 8 cm, or 48 cm^2

and so we end up with the volume V = (1/3)(base area)(height), or

                                                           V = (1/3)(48 cm^2)(√191 cm), or

                                                                  roughly 221.12 cm^3

boxplot e is the answer

6. 104

7. 52/37

8. 2704

9. 140608

10. -52

11. |52|=52

12. 1/52

13. 156

14. 26

15. 40

16. 37

17. -364

18. 53 1/3

19. 50.96

20. 43 2/3

21. 78

22. 50.75

23. 47.63

24. 163.28

25. 10400

26. 338

27. 208

28. 2704 square inches

29. 312 square meters

30. don't know what its asking, tell me so i can tell you

31. 8490.56

32. 52 degrees would be an acute angle

33. 128 degrees

34. 20.8

35. 39

36. 208