HELP!

Please answer i)

(i) The increase expected in the share price between the first year and the third year is $0.90

(ii) The 10th year

Step-by-step explanation:

(i) The given relation is

In the first year, we have t = 1, which gives;

In the third year, we have t= 3 which gives;

Therefore, the increase expected in the share price between the first year and the third year is $5.93 - $5.03 = $0.90

(ii) When the share price value becomes >$7.00, we have;

Which gives;

7 - 2.95 = 2·㏒(10·t + 1)

4.05/2 = ㏒(10·t + 1)

2.025 = ㏒(10·t + 1)

105.93 = 10·t + 1

104.93 = 10·t

t = 104.93/10 = 10.493 ≈ 10.5 years which is within the 10th year.

answer:

3 bags of apples and 2 bags of oranges.

step-by-step explanation: