The area of a sector of a circle is given by the equation , where r is the radius of the circle and S is the angle measure of the sector. If Mia solved this equation for S, which of the following equations did she write?

This question is incomplete

Complete Question

The area of a sector of a circle is given by the equation A = πr²S/360 where r is the radius of the circle and S is the angle measure of the sector. If Mia solved this equation for S, which of the following equations did she write?

a) 360A+ πr²

b) 360A - πr²

c) 360 + A / πr²

d) 360A/ πr²

d) 360A/ πr²

Step-by-step explanation:

In the above question,

Area of the sector (A) = πr²S/360

r = radius

We are also told that Mia solved for S = Angle measure of the sector.

In other to find the equation that Mia used to solve for S,

We would use the Subject of the formula method.

Area of the sector (A) = πr²S/360

We cross Multiply

360 × A = πr²S

Making S the subject of the formula, we divide both sides by πr²

360 × A / πr² = πr²S/ πr²

S = 360 × A/ πr²

S = 360A/ πr²

Therefore, the equation Mia wrote if she solve this equation ( A = πr²S/360) for S is :

S = 360A/ πr²

Option d is the correct option.

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

thats not a system of equations, that is a solution