A first number plus twice a second number is 14. Twice the first number plus the second totals 13. Find the numbers.

The first number is 4 and the second is 5

Step-by-step explanation:

Let's say the first number is x and the second is y:

x+2y=14

2x+y=13

I'll use the linear combination method to solve this.

  2x+4y=28

-  2x+y=13

3y=15

y = 5

x = 4

Hope it helps <3

y=1

x=12

Step-by-step explanation:

Let the first number be x

Let the first number be y

Given:

x+2y=14

2x+y=13

Substitution:

x=14-2y

Solution:

2x+y=13

14-2y+y=13

-2y+y=13-14

-y=-1

y=1

x=14-2y

x=14-2(1)

x=14-2

x=12

Proof:

1) x+2y=14

12+2(1)=14

12+2=14

14=14

Hope this helps ;) ❤❤❤

Let me know if there is an error in my answer

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: