A private jet can fly 1,095 miles in 3 hours with a tailwind but only 987 miles in 3 hours into a headwind find the speed of the jet in still air

The speed of the jet is 347 mph and the  speed of the wind is 18 mph.

Step-by-step explanation:

We have the following:

x = the speed of the jet in still air.

y = the speed of the wind

we know that the speed is equal to:

v = d / t

therefore the distance would be:

d = v * t

if we replace with the information of the exercise we have:

3 * (x + y) = 1095

3 * (x - y) = 987

we must solve this system of equations, add both equations and we are left:

3 * x + 3 * y = 1095

3 * x - 3 * y = 987

3 * x + 3 * y + 3 * x - 3 * y = 1095 + 987

6 * x = 2082

x = 2082/6 = 347

now to calculate y, we replace:

3 * (347 + y) = 1095

1041 + 3 * y = 1095

3 * y = 1095 - 1041

y = 54/3 = 18

The speed of the jet is 347 mph and the  speed of the wind is 18 mph.

step-by-step explanation:

this is not a question

table 3 represents a direct variation function. : )