If $y^2= 36$, what is the greatest possible value of $y^3$?

The greatest possible value of

Step-by-step explanation:

We have the statement , and we have to find the greatest possible value of , first we need to find the value of y.

, to get the y by itself on the left side, we need to take the square root of both sides. The square root of is y, because y*y = , and the square root of 36 is 6 or -6.

We now need to find the greatest value of . When we plug in 6 to , we get positive 216, and when we plug in -6, we get -216. We need to find the greatest possible value, so in this case we compare 216 and -216, 216 is greater than -216, so the answer would be positive 216.

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