A rectangle is 15cm wide, and its length was increased by 2cm, if its new perimeter is 70cm. what is its original length? pls solve

14 cm

Step-by-step explanation:

If the rectangle is 15 cm wide then the total width is 30.

So we can subtract 30 from 70,

=40

If the length is increased by 2 then there is 4 more cm added to the total length.

We can do, 40-4

=38

If 38 is the total length we do 38 ÷ 2

=14

Thus,

The original length was 14 cm.

18cm

Step-by-step explanation:

We can set up an equation to solve this

Let's start by naming the original length before the increase x.

New length is x+2.

Formula for perimeter of a rectangle is 2L+2W=P

Plug known values in

2(x+2)+2(15)=70

Simplify

2x+4+30=70

2x+34=70

2x=36

x=18

The original length is 18cm.

just needed some points but try socratic

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130