Find the factors of the polynomial 45 x2 - 20 y2

5(3x - 2)(3x + 2)

Step-by-step explanation:

Please indicate exponentiation with " ^ " :  45 x^2 - 20 y^2.

Identify the GCF and factor it out:  5(9x^2 - 4y^2)

Recognize that (9x^2 - 4y^2) is the difference of two squares, which factors into (3x - 2y)(3x + 2y)

Then   45 x^2 - 20 y^2 = 5(3x - 2)(3x + 2)

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0