Determine the equation for a line perpendicular to y=1/3+4 and has an x-intercept of 2.

y = -3x + 6

Step-by-step explanation:

Any line perpendicular to

y = (1/3)x + 4

has a slope of -1/(1/3) = -3

and equation

y = -3x + b  (1)

If the line has an x intercept of 2 at (0,2), then

0 = -3(2) + b

solving

b = 6

By substituting b=6 into (1), the line required

y = -3x + 6

y = -3x + 2

Step-by-step explanation:

y=

Slope

slope of the perpendicular line = =

b= 2

Slope intercept form of required line: y = mx + b

y = -3x + 2

b

2

−

b

b

3

+

7

b

2

+

14

b

+

6

%

−

3

b

3

+

7

b

2

+

14

b

+

6

%

step-by-step explanation:

there is no question content here, but you for the free points! : d