Find the area of triangle whose vertices are (- 8,4 )(- 6,6) and (- 3,9)

Area of the triangle = 0

Step-by-step explanation:

We are given the vertices of a triangle as: (- 8,4 ), (- 6,6), (- 3,9)

The formula to find the Area of the triangle =

1/2[ x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)]

Where :

(x₁, y₁) =  (- 8,4 )

(x₂, y₂) = (- 6,6)

(x₃, y₃) =  (- 3,9)

Area of the triangle = 1/2[-8(6 - 9) + -6(9 - 4) + -3(4 - 6)]

= 1/2[ (-8 × -3) +( -6 × 5) +( -3× -2)]

= 1/2[ 24 - 30 + 6)

= 1/2[ 24 + 6 - 30]

= 1/2 [30 - 30]

=1/2[ 0 ]

= 0

Therefore, the area of triangle whose vertices are (- 8,4 ), (- 6,6) and (- 3,9) is ZERO( = 0 )

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation:

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: