A cash register contains $10 bills and $20 bills with a total value of $520. If there are 32 bills total, then how many of each does the register contain

12 is the number of $10 bills

20 is the number of $20 bills

Step-by-step explanation:

Hello,

Let's note

a    the number of $10 bills

b    the number of $20 bills

The total value is $520 so we can write the first equation (1)

We know that there are 32 bills in total so we can write the second equation (2)

(1) - 10*(2) gives

10a + 20b - 10(a+b) = 520 - 320 = 200

10a + 20b - 10a - 10b = 10b = 200

So b = 200/10=20

and then from (2) a = 32 - 20 = 12

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

8

step-by-step explanation:

this is a subtraction problem.

10 - 2 = 8

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's