Solve this application problem using a system of equations: The Bright College footballteam scored 80 times last season, some on seven-point touchdowns and some on three-point field goals. The 80 scores accounted for 516 points. How many touchdowns and field goals did they score

Step-by-step explanation:

Hello,

Touchdown is 7 points, field goals is 3 points

Let's note a the number of touchdowns and b the number of field goals, we can write

   (1)    a + b = 80

   (2)    7a + 3b = 516

(2) - 3*(1) gives

7a + 3b - 3(a + b) = 516 - 3*80

<=> 7a + 3b -3a - 3b = 516 - 240 = 276

<=> 4a = 276

<=>

And then from (1) b = 80 - 69 = 11

Hope this helps

not sure but it may be b, as i said i'm not sure.

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.